2x^2-2450=0

Solution for 2x^2-2450=0 equation:

2x^2-2450=0

a = 2; b = 0; c = -2450;
Δ = b2-4ac
Δ = 02-4·2·(-2450)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-140}{2*2}=\frac{-140}{4}
=-35
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+140}{2*2}=\frac{140}{4}
=35
$